Quadratic Functions
- Find the set of values of
, where , for which the equation has two distinct roots.
Solutions
For two distinct roots,
- The graph shows the curve
.

Find the values ofand .
Hint
Use the completed square form of a quadratic, and use the turn point and y-intercept to find all parameters.
Solutions
The turning point is at
, so the completed square form is:
The y-intercept is at
, so substituting these values in gives:
Substituting back into the completed square form gives:
So, ,
and
.
Substituting
So,
- The quadratic equation
has equal roots.
(a) Find the value of.
Solutions
For equal roots, the discriminant
.
(b) Solve the equation
.
Solutions
Substituting
into the equation gives:
- In this question you must show detailed reasoning.
Show that the equationhas no real roots.
Solutions
Rearranging the equation gives:
Calculating the discriminant:
Since , the equation has no real roots.
Calculating the discriminant:
Since
- Solve these equations, giving your answers in exact form.
(a)
Solutions
Let
. Then the equation becomes:
Substituting back for gives:
Substituting back for
(b)
Solutions
Let
. Then the equation becomes:
Substituting back for gives:
Substituting back for
- (a) Express
in the form .
Solutions
(b) The curve
has a minimum point at
.
Find the values of and
.
Find the values of
Solutions
Use the form obtained in question a and the turning point to find
and
.
We have:
At the minimum point,
and
. Substituting these values in gives:
solve above:
- The diagram shows a right-angled triangle. Find the value of
, correct to 3 s.f.
Solutions
Using Pythagoras’ theorem:
Using the quadratic formula:
Since must be positive:
Since
- Amy throws a ball so that when it is at its highest point, it passes through the centre of a hoop. The path of the ball is modelled by the equation
, where is the height of the ball in metres above the ground and is the horizontal distance in metres from the point at which the ball was thrown. The centre of the hoop is at the point where and .
(a) Find the values ofand .
Hint
Use the completed square form of a quadratic and turning point to find
and then substitute to find
.
The turning point is at .
The turning point is at
Solutions
Use the completed square form to find
since the highest point is at
.
So, and
.
So,
(b) Find the value of
at which the ball hits the ground.
Hint
When the ball hits the ground,
. Set
and solve for
.
Solutions
To find when the ball hits the ground, set
and solve for
:
Using the quadratic formula:
Since must be positive:
Using the quadratic formula:
Since